1/2048=(1/2)^n-1

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Solution for 1/2048=(1/2)^n-1 equation: 



1/2048=(1/2)^n-1

We move all terms to the left:

1/2048-((1/2)^n-1)=0



Domain of the equation: 2)^n-1)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-((+1/2)^n-1)+1/2048=0

We calculate fractions


()/2^n-1)*2048)+2n/2^n-1)*2048)=0

We calculate fractions


(()*2^n)/4n^2+(-1)*2048)+2n*2^n)/4n^2=0

We multiply all the terms by the denominator


(()*2^n)+(-1)*2048)+2n*2^n)=0



We calculate terms in parentheses: +(()*2^n), so:

()*2^n



We get rid of parentheses

(()*2^n)-1)*2048)+2n*2^n=0



We calculate terms in parentheses: +(()*2^n), so:

()*2^n





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